The average density of the peat moss in units of g/cm³ is 2.52 g/cm³
<h3>How to convert 40 lb to grams (g)</h3>
We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:
1 lb = 453.592 g
Therefore,
40 lb = (40 × 453.592) / 1 lb
40 lb = 18143.68 g
<h3>How to convert 1.9 gal to cm³</h3>
We can convert 1.9 gal to cm³ as follow:
1 gal = 3785.41 cm³
Therefore,
1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal
1.9 gal = 7192.279 cm³
<h3>How to determine the density </h3>
The density can be obtained as follow:
- Mass = 18143.68 g
- Volume = 7192.279 cm³
- Density =?
Density = mass / volume
Density = 18143.68 / 7192.279
Density = 2.52 g/cm³
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Answer:The surface heated air expands as it warms, becomes less dense than surrounding cooler air and rises as buoyant and turbulent bubbles. This is convection and is the main process by which the troposphere mixes and heats. Although convection stirs and mixes the troposphere, the higher it is the colder it becomes.
Explanation: Read this and you'll get your answer~! I hope i helped you~! Have an GREAT day too~! <\3
Explanation:
Both conduction and convection are both forms of heat transfer from one place to another.
- In conduction, there must be contact between two bodies for the process to take place but in convection, the matter moves to transfer heat.
- Conduction mostly occurs in solid substances whereas convection occurs mostly in fluids.
- Heat transfer in conduction is quite slow compared to convection which is much faster.
Example of conduction is heating of iron pot when cooking
Example of convection is the refrigerating system.
I answered all of them except 2 for you to do
Hope this helps :))
Answer:
1. The electronic configuration of X is: 1s2 2s2 sp6 3s2
2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6
3. The formula of the compound form by X and Y is given as: XY
Explanation:
For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:
1s2 2s2 sp6 3s2
To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:
Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below
1s2 2s2 2p4
The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6
The formula of the compound form by X and Y is given below :
X^2+ + Y^2- —> XY
Their valency will cancel out thus forming XY
