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STALIN [3.7K]
3 years ago
10

Can you help with all math questions?

Mathematics
2 answers:
forsale [732]3 years ago
7 0
No but , they can be pretty easy sometimes
morpeh [17]3 years ago
6 0
Maybe but i don’t really know
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Let g(x) = 3x + 2. If g(x) = 11, what is x?
astraxan [27]

Answer:

3=x

Step-by-step explanation:

11=3x+2

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What is 2/10 as a percent
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2/10 as a percent would be 20%.
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What is the 1's value in 987,164.302
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A pair of jeans at a store in Seattle costs $220. Since the jeans are from last season, they are 15% off. Because of a Thanksgiv
Lostsunrise [7]

The total percent discount on the jeans is 35% amounting to $77

<h3>Discount</h3>

  • Cost of a pair of jean = $220

  • Discount from last season = 15%
  • Discount from Thanksgiving day = 20%

Total percentage discount = 15% + 20%

= 35%

Amount of discount = Total percentage discount × Cost of a pair of jean

= 35% × $220

= 0.35 × 220

= $77

Therefore, the total percent discount on the jeans is 35% amounting to $77

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brainly.com/question/7459025

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6 0
1 year ago
For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 50
Volgvan

Answer:

P(\bar X>530)=1-0.808=0.192

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the scores, and for this case we know the distribution for X is given by:

X \sim N(\mu=505,\sigma=170)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(505,\frac{170}{\sqrt{35}})

2) Calculate the probability

We want this probability:

P(\bar X>530)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >530)=1-P(Z

P(\bar X>530)=1-0.808=0.192

3 0
3 years ago
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