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2 years ago

I need help asap this is urgent

Mathematics

2 answers:

fiasKO [112]2 years ago

8 0

Girl pls thats just give up that’s not gonna help you in life it’s ok because I failed too

yaroslaw [1]2 years ago

5 0

Answer:

Step-by-step explanation:

I don't know love you tho

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Simplify 3 times x² times y times 4z times x times 2y times z

Ludmilka [50]

Answer:

3(x^2 x Y)(4z x X)(2y x Z)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Kendall is making greeting cards, which she will sell by the box at an arts fair. She paid $40

natta225 [31]

Answer:

Step-by-step explanation:

40 dollars due up front

10 dollars made per sale

5 dollars lost per creation

Realistically speaking she is only making a $5 profit per box she sells;

$5 used up for material cost, $10 made from sales -5+10= 5

To pay the $40 dollar for the booth she would need to make 9 sales with her current profit

40/5 = 9

5 0

2 years ago

Sea World has 9 aquariums with small fish in them and the number of fish in each tank are shown below:45,10,48,19,36,25,63,14,37

zepelin [54]

Answer:

Step-by-step explanation:

Add all the numbers

Divide by 9

5 0

3 years ago

What is true about a rhombus and square?

Genrish500 [490]

Answer:

B. all of these are true

Step-by-step explanation:

The Square is a rhombus because all the sides of a square are equal in length. Even, the diagonals of both square and rhombus are perpendicular to each other and bisect the opposite angles. Therefore, we can say the square is a rhombus.

Hope this helped!!

5 0

3 years ago

Consider two people being randomly selected. (For simplicity, ignore leap years.)

inna [77]

Answer:

$(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}$

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

$=\frac{12}{365} X\frac{12}{365} = \frac{144}{133225}$

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on same day of same month) = 1

P(2 people selected not having birthday on same day of same month):

$= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}$

P(2 people selected have birthday on the same day of same month) $= 1-\frac{364}{365} \\\\= \frac{1}{365}$

7 0

3 years ago