Answer:
Yes
Step-by-step explanation:
Answer:
To prove:
X+Y.Z=(X+Y).(X+Z)
Taking R.H.S
= (X+Y).(X+Z)
By distributive law
= X.X+X.Z+X.Y+Y.Z --- (1)
From Boolean algebra
X.X = X
X.Y+X.Z = X.(Y+Z)
Using these in (1)
=X+X(Y+Z)+Y.Z
=X(1+(Y+Z)+Y.Z --- (2)
As we know (1+X) = 1
Then (2) becomes
=X.1+Y.Z
=X+Y.Z
Which is equal to R.H.S
Hence proved,
X+Y.Z=(X+Y).(X+Z)
Answer:
5/8
Step-by-step explanation:
A. 2/3 × 4/5 × m = 1/3 B. 4/5 × 2/3 × m = 1/3
8/15 × m = 1/3 8/ 15 × m = 1/3
m = 1/3 ÷ 8/15 m = 1/3 ÷ 8/15
m = 1/3 ×15/8 m = 1/3 × 15/8
m = 5/8 m = 5/8
C. 2/3 × 4/5 = 1/3 ÷ m
8/15 = 1/3 × 1/m
8/15 = 1/3m cross multiply
(3m) × (8) = 15
24m = 15
m = 15/24
m= 5/8
Let the two numbers be x and y.
x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________
2x = 98
x = 98/2
x = 49
From x + y = 86
49 + y = 86
y = 86 - 49
y = 37
The numbers are 49 and 37.
