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QveST [7]
3 years ago
14

What is the cosine ratio for angle F?

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0

ANSWER

\cos( \angle \: F)  =  \frac{5}{13}

EXPLANATION

The side length adjacent to <F is 5 units.

The length of the hypotenuse is 13 units.

The cosine ratio is

\cos( \angle \: F)  =  \frac{adjacent}{hypotenuse}

This implies that:

\cos( \angle \: F)  =  \frac{5}{13}

The fourth choice is correct.

AnnZ [28]3 years ago
5 0

hope this answer your question :)

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Which expression is equivalent to (-4y-x)-(y-9x) ?
777dan777 [17]

Answer:

-5y + 8x

Step-by-step explanation:

(-4y-x)-(y-9x)\\\\-4y-x-(y-9x)\\\\\rightarrow-(y-9x)*-1=-y+9x\\\\-4y-x-y+9x\\\\-4y-y+9x-x\\\\\boxed{-5y+8x}

7 0
2 years ago
What is the slope of the line that passes through the points (7,26) and (12, -39)?​
Elena-2011 [213]
The slope (m) = -13.

We can use the slope formula:

m = (y2 - y1) / (x2 - x1)

Let (x1, y1) = (7, 26)
(x2, y2) = (12, -39)

Plug in the values into the formula:

m = (y2 - y1) / (x2 - x1)
m = (-39 - 26) / (12 - 7)

m = -65/5

m = -13
7 0
2 years ago
Ints) Let a, b, and c be positive numbers. Which of the following statements are always true?
blondinia [14]

Answer:I don’t understand

Step-by-step explanation:just re Wright it and I’ll give you da answer;)

4 0
3 years ago
Write the equation of the polynomial below in factored form .
stiv31 [10]

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Step-by-step explanation:

7 0
2 years ago
If a point P(x,y) is the equidistant from the points A(2,3) and B(6,1), find the equation of locus of moving point P.​
jekas [21]

Answer:

y=2x-6

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

d_1=\sqrt{(x-2)^2+(y-3)^2}

The distance d2 from (x,y) to (6,1) is:

d_2=\sqrt{(x-6)^2+(y-1)^2}

Since d1=d2:

\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}

Squaring both sides:

(x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2

Operating:

x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1

Simplifying all the squares:

-4x+4x+4-6y+9=-12x+36-2y+1

Moving the variables to the left side and the numbers to the right side:

-4x+12x-6y+2y=36+1-4-9

Simplifying:

8x-4y=24

Dividing by 4:

2x-y=6

Or, equivalently:

\boxed{y=2x-6}

7 0
3 years ago
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