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Alborosie
3 years ago
8

2 sandwiches and 3 croissants costs £11.

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

The price of a sandwich is £2.5 and the price of a croissant is £2

Step-by-step explanation:

Let s be the number of sandwiches and c be the number of croissants

Then according to given statements the equations will be:

2s+3c = 11\ \ \ \ \ \ \ Eqn\ 1\\3s+6c =19.50\ \ \ Eqn\ 2

Multiplying equation 1 by 2 and subtracting equation 2 from the new equation

2(2s+3c) = 11*2\\4s+6c = 22

Now

4s+6c-(3s+6c) = 22-19.50\\4s+6c-3s-6c = 2.5\\s = 2.5

Putting s=2.5 in equation 1

2(2.5)+3c = 11\\5+3c = 11\\3c = 11-5\\3c = 6\\\frac{3c}{3} = \frac{6}{3}\\c = 2

Hence,

The price of a sandwich is £2.5 and the price of a croissant is £2

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If a population of dolphins increases at a constant rate of 1.5% every year for 20 years what will be the total percentage incre
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Answer:

The population increased by 34.69% over 20 years.

Step-by-step explanation:

It is given that the population of dolphins increases at a constant rate of 1.5% every year for 20 years.

Formula for population increase:

P=a(1+r)^t

where, a is initial population, r is growth rate and t is time in years.

If the population of dolphins increases at a constant rate of 1.5% every year for 20 years, then the population after 20 years is

P=a(1+0.015)^{20}

P=a(1.015)^{20}

P=1.346855a

Where, a is the initial population.

The total percentage increase over the 20 years is

\% change=\frac{P-a}{a}\times 100

where, P is population after 20 years and a is initial amount.

\% change=\frac{1.346855a-a}{a}\times 100

\% change=\frac{0.346855a}{a}\times 100

\% change=0.346855\times 100

\% change=34.6855

\% change\approx 34.69

Therefore the population increased by 34.69% over 20 years.

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