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Y_Kistochka [10]
3 years ago
11

What is the greatest common factor of 5xy and 20x

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

5x

Step-by-step explanation:

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Each edge of a cube is 9 centimeters long. Find the total length of all the edges of the cube.
posledela

Answer:

108 centimeters

Step-by-step explanation:

There are 12 edges total.

9 x 12 = 108

4 0
3 years ago
write two different expressions that are equivalent to 12-15x use factoring to write one of the expressions
sineoko [7]
6×2-5(3x) i think this is one
3 0
3 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
Please help me somebody! PLeaseee!
Solnce55 [7]
It should be Expand by distributing terms.
8
×
7
+
8
x
8×7+8x

2 Simplify
8
×
7
8×7 to
5
6
56.

56+8x
ANSWER: 56+8x
3 0
3 years ago
Equivalent to y-0.32y
larisa86 [58]
Y-0.32y  if you factor you would see:

y(1-0.32)

y(0.68) so

0.68y  or even 68y/100=17y/25  are equivalent....
3 0
3 years ago
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