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Mazyrski [523]
3 years ago
14

Ariana invested $400 in an account paying an interest rate of 3.8% compounded monthly. Assuming no deposits or withdrawals are m

ade, how much money, to the nearest ten dollars, would be in the account after 11 years?
Mathematics
1 answer:
posledela3 years ago
5 0

Answer:

After 11years there'll be$602.880

Step-by-step explanation:

Amount after 11years

=$400(1+3.8/100)¹¹

=$602.880

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Identify the factored form of each polynomial. 4r + 11x + 6 4x + 10x + 6 11. 4r + 14x +6 (4x+3)(x+2) :: (x+3)(4x + 2) :: (2x+3)(
Neporo4naja [7]

Answer:

1) 4x^(2)+11x+6 Factored--> (4x+3) (x+2)

2) 4x^(2)+10x+6 Factored--> (2x+3)(2x+2)

3) 4x^(2)+14x+6 Factored--> (x+3)(4x+2)

Step-by-step explanation:

Factor: 4x^(2)+11x+6 (<em>step by step)</em>

<em>1) Split the second term (11x) into two terms</em>

<em>       </em>4x^2 + 8x + 3x + 6

<em>2)Factor out common terms in the first two terms, then in the last two terms.</em>

      4x(x + 2) + 3(x + 2)

<em>3) Factor out the common term x + 2</em>

<em>      </em> (x + 2) (4x + 3)

Repeat the above steps for similar questions!

4 0
3 years ago
What is the equation of the line that passes through the points (-1, 1.5) and (0.5, 0.5)
Step2247 [10]

The slope-point formula:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have:

(-1,\ 1.5)\to x_1=-1,\ y_1=1.5\\(0.5,\ 0.5)\to x_2=0.5,\ y_2=0.5

Substitute:

m=\dfrac{0.5-1.5}{0.5-(-1)}=\dfrac{-1}{1.5}=-\dfrac{1}{\frac{3}{2}}=-\dfrac{2}{3}\\\\y-1.5=-\dfrac{2}{3}(x-(-1))\\\\y-1.5=-\dfrac{2}{3}x-\dfrac{2}{3}\\\\y-\dfrac{3}{2}=-\dfrac{2}{3}x-\dfrac{2}{3}\ \ \ |+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2}{3}+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2\cdot2}{3\cdot2}+\dfrac{3\cdot3}{2\cdot3}\\\\y=-\dfrac{2}{3}x-\dfrac{4}{6}+\dfrac{9}{6}\\\\y=-\dfrac{2}{3}x+\dfrac{5}{6}

6 0
3 years ago
To avoid a storm, a passenger-jet pilot descended 0.57 mile in 0.6 minute. What was the plane's average change of altitude per m
Elan Coil [88]

Answer:

0.95 miles/minute

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