An injective function is not a function that is surjective. This means that you want a function that has a unique output for each input, that doesn't cover the natural numbers.
In formal terms a function [Math Processing Error] is injective if [Math Processing Error] implies [Math Processing Error].
We also know that it's not surjective because no value maps to [Math Processing Error] (or any odd number) since if [Math Processing Error], then [Math Processing Error]. However, since [Math Processing Error], the function isn't surjective.
Answer is B.
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Answer:
y - 1 = 1/6x + 1 <<< Point slope form
y = 1/6x + 2 <<< slope intercept form
Either one works unless the question specifies the form of the equation
Step-by-step explanation:
Point slope form: (y - y1) = m(x - x1)
Given: (-6,1) ; m = 1/6
(y - 1) = 1/6(x - (-6))
y - 1 = 1/6x + 1 <<< Point slope form
y = 1/6x + 2 <<< slope intercept form: y = mx + b
Answer:
it's geometric
Step-by-step explanation:
geometric equations change by a rate witch means you multiply to get to the next number in the sequence
arithmetic you add to get to the next number in the sequence
Answer:
The answer is on the paper. Hope it's correct :)
