3 years ago

Using the Distance Formula to find the distance between the two points. A (-3,4) B (1,3)

Mathematics

2 answers:

Vikki [24]3 years ago

4 0

All i know is that distance isnt my thing and i dont know how to do it

Setler79 [48]3 years ago

4 0

Distance AB= root (1+3)^2-(3-4)^2
= root 16-1
= root 15 units

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3 years ago

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3 years ago

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ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

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$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

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LHL=RHL= $\frac{1}{2}$

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$LHL=RHL\neq f(2)$

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4 years ago