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Law Incorporation [45]
3 years ago
12

Brent bought 6 potted plants for his co-workers. Each plant cost $7.91. How much money did he spend on his co-workers?

Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

C. because 7.91. x 6 is 47.46

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Hey Guys! I need some help. This is the question... Sara travels often for her job. The miles she traveled for the last seven wo
Schach [20]

Using the median concept, it is found that the interquartile range of Sara's daily miles is of 21 miles.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the quartiles.

The ordered data-set is given as follows:

65, 72, 86, 88, 91, 93, 97

There are 7 elements, hence the median is the 4th element, of 88. Then:

  • The first half is 65, 72, 86.
  • The second half is 91, 93, 97.

Since the quartiles are the medians of each half, the have that:

  • The first quartile is of 72 miles.
  • The third quartile is of 93 miles.
  • The interquartile range is of 93 - 72 = 21 miles.

More can be learned about the median of a data-set at brainly.com/question/3876456

#SPJ1

4 0
2 years ago
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0
3 years ago
Find x, round to the nearest tenth degree.
Romashka [77]

Answer:

Step-by-step explanation:

Use the Law of Cosines

A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°

5 0
3 years ago
Please please please help me show your work (10 points!!)
Shkiper50 [21]

Answer:

C or 8

Step-by-step explanation:

Once again, first you ant to simplify the equation before putting in the numbers.  So the simplified equation is mh + mp -p/h +m. Then you put the numbers in. mh is actually 3(-1), which is -3. mp is really 3*4, which is 12. p/h is 4/-1, which is -4, and then you add m. So when you put the numbers is it ends up as -3 + 12 - 4 +3, which simplified is 8, or C

8 0
3 years ago
Read 2 more answers
Can someone help with this
Zinaida [17]

Answer:

C and E

Step-by-step explanation:

-2/3 = -0.66

so hence forth

2/3 = 0.66

- (2/3) = -0.66 and

2/-3 = -0.66

5 0
3 years ago
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