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Nitella [24]
3 years ago
9

What is the value of x?​

Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

Where is your question?

Step-by-step explanation:

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viva [34]

Step-by-step explanation:

Given g'(x) = g^{-2}, x> 0\ g(1) = 0 \ and \ g(2) = 0

To get g(x), we will have to integrate g'(x)

g(x)  = \int\limits {x^{-2}} \, dx\\ g(x)  = \frac{x^{-2+1}}{-2+1} + C\\ g(x) = -x^{-1} + C\\g(x) = -x^{-1} + C\\

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g(x) = -x⁻¹ + 1

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3 0
3 years ago
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