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Flauer [41]
3 years ago
14

on selling a fan for rupees 4700 A shopkeeper loses 6% at what price must he sell it to gain 6 percentage ​

Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Given:

Selling price of a fan = Rs.4700

Loss percent = 6%

To find:

The price at which he must sell it to gain 6 percentage.

Solution:

Let x be the cost price of the fan.

Loss percent = 6%

Selling price = Cost price - 6% of cost price

S.P.=x-\dfrac{6}{100}x

S.P.=x-0.06x

S.P.=0.94x

Selling price of a fan = Rs.4700

4700=0.94x

\dfrac{4700}{0.94}=x

5000=x

So, the cost price of the fan is Rs.5000.

Now, he need to sell this fan in 6% gain.

Selling price = Cost price + 6% of cost price

S.P.=5000+\dfrac{6}{100}\times 5000

S.P.=5000+300

S.P.=5300

Therefore, he must sell it for Rs.5300 to gain 6 percentage.

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Answer:  The two roots are x = 3/2 and x = -2

=========================================================

Explanation:

You have the right idea so far. But the two numbers should be 3 and -4 since

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The -1 being the coefficient of the x term.

This means you need to change the -3x and 4x to 3x and -4x respectively. The other inner boxes are correct.

---------

Refer to the diagram below to see one way to fill out the box method, and that helps determine the factorization.

If we place a 2x to the left of -2x^2, then we need an -x up top because 2x*(-x) = -2x^2

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So we have the factor -x-2 along the top

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We have the factor 2x-3 along the left side.

---------

The two factors are (2x-3) and (-x-2) which leads to the factorization (x+3)(-x+2)

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The two roots are x = 3/2 and x = -2

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