A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses
on the first pass, he misses the second pass 20% of the time. What is the probability of missing two passes in a row?
1 answer:
Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
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