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Anvisha [2.4K]
3 years ago
7

A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses

on the first pass, he misses the second pass 20% of the time. What is the probability of missing two passes in a row?
Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P(E) = ?

Event X = Football player misses the first pass

P(X) = 0.4

Event Y = Football player misses just after he first miss

P(Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P(E) = P(X).P(Y)

P(E) = 0.4*0.2

P(E) = 0.08

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