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3 years ago

The area of a rectangle is 80. the length is 2 more than the width. find the dimensions brainly

1 answer:

6 0

The average of the length and width is about √80 ≈ 9. The dimensions will be ±1 from this.

The width is 8, the length is 10.

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What is the interquartile range of the data represented by the box plot shown below?

mezya [45]

Answer:

<h2>The interquartile range is 22.</h2>

Step-by-step explanation:

The box plot shows all three quartiles, where the first one is 45, the second quartile is 50 and the third quartile is 67 (remember that there are only three quartiles in a dataset).

Now, the interquartile range is defined as the difference between the third and first quartile, which in this case is 67 - 45 = 22.

Therefore, the interquartile range is 22.

5 0

3 years ago

Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 12 h using both

Leokris [45]

Answer:

Jim's hose: 27 hours.

Bob's hose: 21.6 hours.

Step-by-step explanation:

Let t represent hours taken by Jim's hose.

Part of pool filled by Jim's hose in 1 hour would be $\frac{1}{t}$ .

We have been given that Bob's hose, used alone, takes 20% less time than Jim's hose alone. This means that Bob's hose take will take 80% time of Jim's hose that is $0.8t$ .

Part of pool filled by Bob's hose in 1 hour would be $\frac{1}{0.8t}$ .

We are also told that it takes 12 hours using both hoses. Part of pool filled by both hoses in 1 hour would be $\frac{1}{12}$ .

Now, we will add rates of both hoses and equate with $\frac{1}{12}$ as:

$\frac{1}{t}+\frac{1}{0.8t}=\frac{1}{12}$

$\frac{0.8}{0.8t}+\frac{1}{0.8t}=\frac{1}{12}$

$\frac{0.8+1}{0.8t}=\frac{1}{12}$

$\frac{1.8}{0.8t}=\frac{1}{12}$

Cross multiply:

$0.8t*1=1.8(12)$

$0.8t=21.6$

$\frac{0.8t}{0.8}=\frac{21.6}{0.8}$

$t=27$

Therefore, it will take 27 hours for Jim's hose to fill the pool alone.

Time take by Jim's hose alone: $0.8t\Rightarrow 0.8(27)=21.6$ .

Therefore, it will take 21.6 hours for Bob's hose to fill the pool alone.

3 0

4 years ago

9.8 ft<br> 4f<br> 12 ft<br> Find the Area of this figure

adoni [48]

I think it’s 470.4 ft

6 0

3 years ago

Nd the value of the expression. Type a numerical answer in the space provided. 4 ∙ 1 - 3^2 ÷ 3

Gemiola [76]

This is a problem of Arithmetic that is a branch of mathematics that consists of the study of numbers. Its main goal is the study of the traditional operations on them just as: <em>addition, subtraction, multiplication and</em><span><em> division</em>. </span>There is an order of operation to solve problems in arithmetic that is the way you choose to simplify expressions. This order is like this:

1. First. Solve Parentheses.
2. Second. Solve Exponents (and root).
3. Third. Solve Multiplication and Division
3. Fourth. Solve addition and subtraction.

So let's apply these concepts to our problem:

$4 \times 1-3^2 \div 3$

We don't have parentheses, so let's apply second step:

$4 \times 1-9 \div 3$

Applying third step:

$4-3$

Finally, applying fourth step, the result is:

$1$

4 0

3 years ago

What is the missing constant term in the perfect square that starts with x squared minus 8x ?

Anettt [7]

Answer:

Step-by-step explanation:

${x}^{2} - 8x + 16 = (x - 4) ^{2} \\$

7 0

3 years ago