Ask question

Ask question

All categories

3 years ago

9

Suppose a railroad is 5 Kilometers and it expands on a hot day by 16 centimeters in length. Approximately how many meters would

the center of the rail rise above the ground?

2 answers:

Butoxors [25]3 years ago

3 0

Answer:

17.32 meters above the ground.

Step-by-step explanation:

ASHA 777 [7]3 years ago

3 0

Answer:

20.0

Step-by-step explanation:

You might be interested in

Which of the following is a composite number?

Sliva [168]

A look up what are composite numbers look at images and it will show you

3 0

3 years ago

Read 2 more answers

A.(x, y) (x -1, y + 4)

attashe74 [19]

The answer is D i believe

8 0

3 years ago

Read 2 more answers

PLEASE HELPP!<br> A square has an area of 5.76cm². Find the perimeter of the square

nikdorinn [45]

The ar. of square =X^
=5.76
So,X=√5.76
=2.4
now, perimeter of square =4(X)
=4(2.4)
=9.6
So, the perimeter of the square is 9.6cm..

Thanks!

Hope it helps you..

4 0

3 years ago

Write an equation that represents the line. Use exact numbers

mestny [16]

The equation that represents the line is:

$y = \frac{5}{6}x+\frac{8}{3}$

Step-by-step explanation:

We have to observe the graph to find the points on line

So the points on line are:

(x1,y1) = (4,6)

(x2,y2) = (-2,1)

First of all we have to find the slope

$m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{1-6}{-2-4}\\=\frac{-5}{-6}\\=\frac{5}{6}$

Equation of line is given by:

$y=mx+b$

Putting the value of slope

$y = \frac{5}{6}x +b$

Putting (4,6) in the equation

$6 = \frac{5}{6}(4)+b\\6 = \frac{20}{6} +b\\b = 6 - \frac[20}{6}\\b = \frac{36-20}{6}\\b = \frac{16}{6}\\b = \frac{8}{3}$

Putting the value of b

$y = \frac{5}{6}x+\frac{8}{3}$

Hence,

The equation that represents the line is:

$y = \frac{5}{6}x+\frac{8}{3}$

Keywords: Equation of line, slope

Learn more about equation of line at:

#LearnwithBrainly

7 0

3 years ago

City Community College plans to increase its enrollment capacity to keep up with an increasing number of student applicants. The

aivan3 [116]

The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now.
at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students.

3 0

3 years ago