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Nata [24]
3 years ago
11

Eight students ran a 180-meter course during their physical education class. The chart shows the time it took each student to co

mplete the course. 180-Meter Course Completion Times Student Time (s) 1 30 2 32 3 33 4 35 5 37 6 38 7 40 8 45 How much faster was the average speed for Student 1 than the average speed
Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

Step-by-step explanation:

Speed of student 1 = 180/30= 6 m/sec

speed of student 2= 180/32= 5.62 m/sec

speed of student 3= 180/33= 5.45 m/sec

speed of student 4= 180/35= 5.14 m/sec

speed of student 5= 180/37= 4.86 m/sec

speed of student 6= 180/38= 4.73 m/sec

speed of student 7= 180/40= 4.5 m/sec

speed of student 8= 180/32= 4 m/sec

average speed is = (6+5.62+5.45+5.14+4.86+4.73+4.5+4)/8

hence, average speed is= 5.04

hence, the average speed of student 1 = 6m/sec

how much faster is average speed of student 1 than average speed= 6- 5.04 = 0.96

hence, average speed of student 1 is 0.96 m/sec more thanthe average speed.

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Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

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Answer:

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Step-by-step explanation:

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