Question

A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.

Answer 1

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Total possible values for a spinner are 3. So, the probability of getting B, we get

$P(B)=\dfrac{1}{3}$

Total possible values for a die are 6. So, the probability of getting 6, we get

$P(6)=\dfrac{1}{6}$

Now, the probability of getting a B and then a 6 is

$P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}$

$P(B,6)=\dfrac{1}{18}$

The required probability is $\dfrac{1}{18}$.

Therefore, the correct option is D.