<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%203%5E4%2B6%5E2" id="TexFormula1" title="\sqrt{x} 3^4+6^2" alt="\sqrt{x} 3^4+6^

Effectus [21]

3 years ago

2" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

= 9√x+36. I believe this is the answer !!!! :)

You might be interested in

Help please.........

Gnoma [55]

Answer:

20x + 15 = 11

Step-by-step explanation:

First you need to add the like terms:

-7+2=-5

Now you need to expand the brackets:

-5*-4x=20x

-5*-3=15

Now you have 20x + 15 = 11. So if you want you can rearrange the formule to find x.

20x=-4

x= -5

8 0

3 years ago

At a certain store a cd cost $12 if the cost or cds were graphed as the output compared to the number of cds purchased as input

xxTIMURxx [149]

I’m pretty sure the answers D

4 0

3 years ago

Kiera already has 12 plants in her backyard and she can also grow 1 plant with every seed packet she uses. How many seed packets

Elza [17]

Answer: 12

Step-by-step explanation: 24 - 12 times 1

7 0

3 years ago

How do I simplify this (sinx)/(secx+1)

pochemuha

Answer:

Step-by-step explanation:

$\frac{sin~x}{sec~x+1} =\frac{sin~x}{\frac{1}{cos~x}+1 } =\frac{sin~x~cos~x}{1+cos~x} \\=\frac{sin~x~cos~x}{1+cos~x} \times \frac{1-cos~x}{1-cos~x} \\=\frac{sin~x~cos~x(1-cos~x)}{1-cos^2 x} \\=\frac{sin~x~cos~x(1-cos~x)}{sin^2x} \\=\frac{cos~x(1-cos~x)}{sin~x} \\=cos ~x(csc~x-cot~x)\\or\\=cot~x(1-cos~x)$

6 0

4 years ago

Sandra has taken 3 Test this Quarter. She has scored an 78%, 76%, and a 93%. Sandra wants to earn at least and 85% for the Quart

algol [13]

Answer:

I think at least a 86% hope this helps, hope i am right

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers