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yawa3891 [41]
3 years ago
5

Why is subtracting an expression similar to distributing a –1?

Mathematics
2 answers:
ki77a [65]3 years ago
7 0

Answer:

b

Step-by-step explanation:

serg [7]3 years ago
5 0

Answer:

You multiply each term inside the parentheses by –1 in order to subtract each term, since subtraction is the additive inverse.

Step-by-step explanation:

You multiply each term inside the parentheses by –1 in order to subtract each term, since subtraction is the additive inverse.

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Please help this is due soon
a_sh-v [17]
For the A parts just make all the second numbers negative example: if it were 5,1 make it (5,-1) and for the B part make all the first numbers a negative example: if it were 5,1 make it (-5,1)
7 0
3 years ago
Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,
Hatshy [7]

Answer: T'(18,36)

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

 A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of \frac{9}{5}, you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.

Knowing that the point T has the following coordinates:

T(10,20)

You get that the coordinates of the Image T' are the shown below:

T'=(\frac{9}{5}*10,\frac{9}{5}*20)\\\\T'=(18,36)

6 0
4 years ago
HELP ILL GIVE 10 PTS quick pleaseee
Sladkaya [172]

Answer: I’m pretty sure it’s the 4th one.

Step-by-step explanation: because 1 and 2 have infinity solutions but 3 has no solution 4 comes up with x=-11

Can you give brainiest? :)

6 0
3 years ago
How many whole groups of 8 can we pull out of 1
vazorg [7]

Answer:

0.125

Step-by-step explanation:

1/8=0.125

4 0
3 years ago
Prove that<br>1/1+root 2 + 1/root2 + root3 + 1/root3 + root4 + 1/root8 +root9 = 2​
daser333 [38]

Step-by-step explanation:

LHS:

\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\ldots \ldots \ldots \ldots \ldots+\frac{1}{\sqrt{8}+\sqrt{9}}1+21+2+31+3+41+……………+8+91

Rationalizing the denominator, we get

\Rightarrow\left(\frac{1}{1+\sqrt{2}} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}\right)+\left(\frac{1}{\sqrt{2}+\sqrt{3}} \times \frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}}\right)+\left(\frac{1}{\sqrt{3}+\sqrt{4}} \times \frac{\sqrt{3}-\sqrt{4}}{\sqrt{3}-\sqrt{4}}\right)+\cdots \ldots+\left(\frac{1}{\sqrt{8}+\sqrt{9}} \times \frac{\sqrt{8}-\sqrt{9}}{\sqrt{8}-\sqrt{9}}\right)⇒(1+21×1−21−2)+(2+31×2−32−3)+(3+41×3−43−4)+⋯…+(8+91×8−98−9)

We know that,

\left(a^{2}-b^{2}\right)=(a+b)(a-b)(a2−b2)=(a+b)(a−b)

Now, on substituting the formula, we get,

=\frac{1-\sqrt{2}}{1-2}+\frac{\sqrt{2}-\sqrt{3}}{2-3}+\frac{\sqrt{3}-\sqrt{4}}{3-4}+\cdots \ldots \cdot \frac{(\sqrt{8}-\sqrt{9})}{8-9}=1−21−2+2−32−3+3−43−4+⋯…⋅8−9(8−9)

\Rightarrow \frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\cdots+\frac{1}{\sqrt{8}+\sqrt{9}}=(\sqrt{2}-1)+(\sqrt{3}-\sqrt{2})+(\sqrt{4}-\sqrt{3})+\cdots+(\sqrt{9}-\sqrt{8})⇒1+21+

4 0
3 years ago
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