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frozen [14]
2 years ago
12

For each value of u, determine whether it is a solution to 6u-1< −19. u Is it a solution? Yes or No 5 −4 −3 8

Mathematics
1 answer:
Agata [3.3K]2 years ago
7 0

Answer:

No it is not a solution to 6u-1<-19

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I need help with math
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\frac{1}{5}  +  \frac{3}{4}  \times  \frac{3}{5}  =  \\

\frac{1}{5}  +  \frac{9}{20}  =  \\

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\frac{13}{20}  \\

4 0
2 years ago
Select the graph that represents the given set. (Click on the graph until the correct one is showing.) D = {(1, 1), (1, 2), (1,
vichka [17]

Answer: Vertical line x = 1

<u>Step-by-step explanation:</u>

(1, 1) (1, 2) (1, 3) (1, 4)

Notice that the x-value for each coordinate is 1.

The line is a vertical line (up & down) through x = 1

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3 years ago
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-5yards+-8yards=-13yards

8 0
3 years ago
An investor invested a total of $2500 in two mutual funds. One fund earned a 5% profit while the other earned a 3% profit. If th
7nadin3 [17]

Answer:

$500 and $2000

Step-by-step explanation:

Let x represent the total investment = $2500

also, this total is split into two different funds

Lets represent these funds as a and b, such that fund a yields a profit of 3% and fund b yield a profit of 5%

So,

a + b = x

a + b =  2500   ......eq 1

Profit from each fund gives;

0.03 a + 0.05b = 115     ....eq 2

Solve simultaneously using substitution method

From eq 1;

b = 2500 - a

Slot in this value in eq 2

0.03a + 0.05 (2500 - a) = 115

expand

0.03a + 125 - 0.05a = 115

collect like terms

0.03a - 0.05a = 115 - 125

-0.02a = -10

Divide both sides by -0.02

a =  $500

Put this value of a in eq 1

500 + b =  2500

Subtract 500 from both sides

b = 2500 - 500

b = $2000

3 0
3 years ago
The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds
eduard
We have that

<span>p(t)=-3t^2+18t-4

using a graphing tool, we can see the maximum of the graph
(see the attached figure)

A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?

</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)

<span>B) What is the maximum profit? 

23 (hundred of thousand of dollars) = 2.300.000 dollars

</span>c) What time will it be two late?
 
(This is the time when the graph crosses zero and the profits turn into losses )

5.77 years, or an estimate of about  69 months.

4 0
3 years ago
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