You would have to set you problem up like
x 40
____=_____
720 100
you would multiply 40 by 720 then you would divide 28,800 by 100 your answer will be 288.
Answer:
y = 30m and x = 1 h
Step-by-step explanation:
mrsdoughty1 deserves the credit
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
4
Step-by-step explanation:
![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
= ![\sqrt[3]{4*4*4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%2A4%2A4%7D)
=4
Answer:
0.1221
Step-by-step explanation:
