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3 years ago

Answerasap a1324242352352112

Mathematics

1 answer:

makkiz [27]3 years ago

5 0

Answer:

For the first 1, the box plot is more helpful to find the minimum distance. For the second one, the histogram is the best one to find 23 vehicles.

Step-by-step explanation:

Box plots are created based on medium, range, and mode. Histogram can show the exact numbers.

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Help, 3+7x=12, what is x?

liraira [26]

So just your normal equation.
We need to isolate x alone.
First lets write out our equation
3 +7x = 12

Lets do this step by step.

first subtract 3 from both sides.
3 + 7x = 12
-3 = -3 it cancels out on the left side and we solve on the right side.
*************
7x = 9

second we divide both sides by 7
7x = 9
÷7 = 7 we got the x alone and we just write 9/7 as our answer.

x = 9/7

Or as a decimal.
9/7 could be 1.28571428571429

Either will work.
x = 9/7
or
x = 1.28571428571429

Have a nice day. :)

3 0

4 years ago

X2 + 4 = 7x - 3 Quadratic formula

daser333 [38]

Answer:

Step-by-step explanation:

4 0

4 years ago

Find an upper bound and a lower bound for the zeros of the following polynomial function: h(x)=x^4+2x^3-11x^2-14x+24

storchak [24]

Https://www.tiger-algebra.com/drill/x~4-2x~3-13x~2_14x_24=0/

I hope this helps. it has the steps and explanations.

8 0

3 years ago

Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal

Phantasy [73]

Answer:

Part A

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the given values we get;

$The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12$

R = 12 inches

The radius of the circumscribing circle is 12 inches

Part B

The length of each side of the hexagon, 's', is;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

s = 12 inches

The perimeter, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon is 72 inches

Step-by-step explanation:

The given parameters of the regular hexagon are;

The length of the apothem of the regular hexagon, a = 6·√3 inches

The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;

$a = R \cdot cos \left(\dfrac{\pi}{n} \right)$

Where;

n = The number of sides of the regular polygon = 6 for a hexagon

'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;

Part A

Therefore, we have;

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the values gives;

The circumradius, R = 12 inches

Part B

The length of each side of the hexagon, 's', is given as follows;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore, we get;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

The length of each side of the hexagon, s = 12 inches

The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon = 72 inches

5 0

3 years ago

(x-2)+(y-16)=169 what's the circles radius

bija089 [108]

The anwser is x=187-y

4 0

3 years ago