3 years ago

Find an upper bound and a lower bound for the zeros of the following polynomial function: h(x)=x^4+2x^3-11x^2-14x+24

1 answer:

8 0

Https://www.tiger-algebra.com/drill/x~4-2x~3-13x~2_14x_24=0/

I hope this helps. it has the steps and explanations.

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BaLLatris [955]

your answer is 1st quadrant!

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Have a good day <3

3 0

3 years ago

adelina 88 [10]

9514 1404 393

Answer:

(a) 26 units

Step-by-step explanation:

The left-side vertical line extends from y = -3 to y = +3, so is 3-(-3) = 6 units long.

The bottom side horizontal line extends from x = -5 to x = 2, so is 2 -(-5) - 7 units long.

The sum of these two sides is 6 + 7 = 13 units. These two sides make up half of the perimeter, which is the total length of all four sides.

The perimeter is 2 × 13 units = 26 units.

7 0

2 years ago

Julli [10]

Answer:

$5 {x}^{2} - x + 6$

Step-by-step explanation:

The solution is in the image

5 0

2 years ago

arsen [322]

For $x$ , $x-5$ , therefore $|x-5|=-(x-5)=-x+5$

So, for $x$ , $5x-|x-5|=5x-(-x+5)=5x+x-5=6x-5$

8 0

3 years ago

NikAS [45]

Answer: The conculsion is you lost some teath

Step-by-step explanation:

5 0

3 years ago