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lord [1]
3 years ago
13

Find an upper bound and a lower bound for the zeros of the following polynomial function: h(x)=x^4+2x^3-11x^2-14x+24

Mathematics
1 answer:
storchak [24]3 years ago
8 0
Https://www.tiger-algebra.com/drill/x~4-2x~3-13x~2_14x_24=0/

I hope this helps. it has the steps and explanations.
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An expression is given that has a value between 4.44.4 and 4.54.5, and where xx represents an integer. ​ ​ \sqrt{x}+\sqrt{x} x ​
musickatia [10]

Answer:

x = 5

Step-by-step explanation:

Given

\sqrt x + \sqrt x = (4.4,4.5)

Required

Find x

When the result is 4.4, we have:

\sqrt x + \sqrt x = 4.4

This gives:

2\sqrt x = 4.4

Divide both sides by 2

\sqrt x = 2.2

Square both sides

x = 2.2^2

x = 4.84

When the result is 4.5, we have:

\sqrt x + \sqrt x = 4.5

2\sqrt x = 4.5\\

Divide both sides by 2

\sqrt x = 2.25

Square both sides

x = 2.25^2

x = 5.0625

So, the value of x is between 4.84 and 5.0625

i.e.

x = (4.84,5.0625)

The only integer between the above interval is 5.

Hence:

x = 5

5 0
3 years ago
I need help with this​
SVETLANKA909090 [29]
I think it could be 64 but I’m not totally sure
5 0
3 years ago
What are the solutions if the equation x^2+4x+4=25
tatiyna

\text{Use}\ (a+b)^2=a^2+2ab+b^2\\\\x^2+4x+4=25\\\\x^2+2(2)(x)+2^2=25\\\\(x+2)^2=25\iff x+2=\pm\sqrt{25}\\\\x+2=-5\ \vee\ x+2=5\qquad\text{subtract 2 from both sides}\\\\\boxed{x=-7\ \vee\ x=3}


Other method:

x^2+4x+4=25\qquad\text{subtracr 25 from both sides}\\\\x^2+4x-21=0\\\\x^2+7x-3x-21=0\\\\x(x+7)-3(x+7)=0\\\\(x+7)(x-3)=0\iff x+7=0\ \vee\ x-3=0\\\\x+7=0\qquad\text{subtract 7 from both sides}\\\boxed{x=-7}\\\\x-3=0\qquad\text{add 3 to both sides}\\\boxed{x=3}

5 0
3 years ago
At gym A, it cost $12 to join with a monthly fee do $20. At gym B, it cost $4 to join with a monthly will the cost of both gyms
Vika [28.1K]
What is the monthly fee at gym b ?
6 0
3 years ago
Here is a sequence
Rina8888 [55]

Answer:

5120

Step-by-step explanation:

....80,160,320.... 2560

You are multiplying by 2 each time.

4 0
4 years ago
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