All categories

3 years ago

Which point on the number line represents an integer? Justify your response.

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

8 0

Answer:

All of them are integers

Step-by-step explanation:

All are numbers of integers so all should be correct

Natasha_Volkova [10]3 years ago

8 0

Answer: p

Step-by-step explanation: an integer is a negative or positive number with no fraction

You might be interested in

Solve the equation using square roots. 3x2 – 27 = 0

Scrat [10]

Answer:

C, Plus or minus 3

Step-by-step explanation:

to solve 3x² - 27 = 0, we want to get the x by itself, so lets add 27 to both sides.

3x² = 27 < divide both sides by 3 to get x alone

3x²/2 =x²

27/3 = 9

x² = 9 < we can use the square-root property and square both sides of the equation to get x alone. we use the ± because there are 2 possible solutions to a square rooted number

√x² = x

√9 = 3

x = ±3

looking at our answer choices, the correct answer is C

4 0

4 years ago

Read 2 more answers

Is the point (-10, -34) on the line y=3x-4

iogann1982 [59]

Yes it is right (-10, 34) is a solution of y = 3x-4

7 0

3 years ago

Can someone help please

nordsb [41]

First you have to find the last side of it.
P= 182

5 0

3 years ago

What is 2 dived by 0.04

Kamila [148]

Answer:

Step-by-step explanation:

The correct answer is 50

4 0

3 years ago

Read 2 more answers

The vertices of a rectangle are located at (1, 2) (5, 0) (2, -6) and (-2, -4) what is the area of the rectangle

galina1969 [7]

Answer:

Option 2) 30 square units

Step-by-step explanation:

step 1

Plot the rectangle to better understand the problem

we have

A(1, 2),B(5, 0),C(2, -6) and D(-2, -4)

see that attached figure

step 2

Find the length of the sides

Remember that'

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

<em>Find the length side AB</em>

we have

A(1, 2),B(5, 0)

substitute in the formula

$d=\sqrt{(0-2)^{2}+(5-1)^{2}}$

$d=\sqrt{(-2)^{2}+(4)^{2}}$

$d_A_B=\sqrt{20}\ units$

<em>Find the length side BC</em>

we have

B(5, 0),C(2, -6)

substitute in the formula

$d=\sqrt{(-6-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(-6)^{2}+(-3)^{2}}$

$d_B_C=\sqrt{45}\ units$

step 3

Find the area of rectangle

The area of rectangle is equal to

$A=LW$

we have

$L=BC=\sqrt{45}\ units$

$W=AB=\sqrt{20}\ units$

substitute

$A=(\sqrt{45})(\sqrt{20})=\sqrt{900}=30\ units^2$

7 0

3 years ago