The shop sold 36 sundaes and 28 banana spilts
<em><u>Solution:</u></em>
Let "a" be the number of sundaes sold
Let "b" be the number of banana spilts sold
Cost of 1 sundaes = $ 2
Cost of 1 banana spilt = $ 3
<em><u>On a hot summer day, the shop sold 8 more sundaes than banana splits and made $156</u></em>
Therefore,
Number of sundaes sold = 8 + number of banana spilts sold
a = 8 + b ------- eqn 1
<em><u>Also, given that they made $ 156</u></em>
<em><u>Therefore, we frame a equation as</u></em>:
Number of sundaes sold x Cost of 1 sundaes + number of banana spilts sold x Cost of 1 banana spilt = 156

2a + 3b = 156 ---------- eqn 2
<em><u>Substitute eqn 1 into eqn 2</u></em>
2(8 + b) + 3b = 156
16 + 2b + 3b = 156
16 + 5b = 156
5b = 156 - 16
5b = 140
<h3>b = 28</h3>
<em><u>Substitute b = 28 in eqn 1</u></em>
a = 8 + 28
<h3>a = 36</h3>
Thus the shop sold 36 sundaes and 28 banana spilts
Answer: The first option, the one in orange.
Step-by-step explanation:
This is the associative property.
Hope this helps, good luck on the test! :)
Hello,
I note (a,b,c) the result of a quarters, b dimes and c pennies:
2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)
106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0