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3 years ago

Can you form a right triangle with the three lengths given? Why or why not?

Mathematics

1 answer:

EastWind [94]3 years ago

7 0

Answer:

Yes, 7^2+24^2=25^2

Step-by-step explanation:

If a right triangle then:

is 7^2+24^2=25^2

rewritten: 49+576=625 then yes

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Please answer this question ASAP

Vilka [71]

Answer:

First, second, third, and fourth are functions

Step-by-step explanation:

Each input in the first, second, third, and fourth only have one output. In the fifth one 3.3 and 6.6 are seen twice as the x-value, so this is incorrect.

(answered this on your other question, but I will put it here too!)

Cada entrada en la primera, segunda, tercera y cuarta tiene solo una salida. En el quinto, 3.3 y 6.6 se ven dos veces como el valor de x, por lo que esto es incorrecto.

(respondí esto en tu otra pregunta, ¡pero también lo pondré aquí!)

3 0

3 years ago

The table shows how much a store charges for certain numbers of pencils. Number of pencils (p) Cost (c) 4 $0.72 7 $1.26 12 $2.16

Arada [10]

Find the rate of change, (y2-y1)/(x2-x1), from the data given...

(2.16-1.26)/(12-7)=0.18

(1.26-0.72)/(7-4)=0.18

Since the rate is constant, this is a linear equation of the form y=mx+b. Furthermore, since 0 pencils cost 0, b=0, so the cost of the pencils is simply the number of pencils times 18 cents...

c(p)=0.18p (cost with respect to pencils is 0.18 times the number of pencils)

7 0

3 years ago

Solve Ax + By = C for x.

Zolol [24]

Answer:

the first option

Step-by-step explanation:

Given

Ax + By = C ( subtract By from both sides )

Ax = C - By ( divide both sides by A )

x = $\frac{C-By}{A}$

7 0

3 years ago

The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length

Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P = 2(L + W) ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

$\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}$

$\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}$

Substitute the value of the Perimeter and the length (L) into the formula:

$\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}$

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

$\displaystyle\mathsf{34\:=14\:+2W}$

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

$\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}$

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

4 0

3 years ago

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

Irina18 [472]

Answer:

helloooooo

Step-by-step explanation:

7 0

3 years ago

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