Answer:
YES
Step-by-step explanation:
just replace x=3, y=2
5.3 - 3.2 = 15 - 6 = 9
so it is a solution
Answer = A). 34 squared minus 16 squared = 900. Square-root that to get 30.
This may not help but the first step is to distribute the 2 to the (x - 3) Which would get you to 2x - 3 + y2= 49 Then you will want to subtract 3 from 49 which gives you 46. Now you have 2x+ y2= 49 Now you need you have the standard equation ax+by=c
Answer:
4°
Step-by-step explanation:
hoped this helped
![e ^{2x} -e ^x=6 ](https://tex.z-dn.net/?f=e%20%5E%7B2x%7D%20-e%20%5Ex%3D6%0A)
----(i)
Let,
![e ^x =t](https://tex.z-dn.net/?f=e%20%5Ex%20%3Dt)
Therefore,
![e^{2x} = t^{2}](https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20t%5E%7B2%7D%20)
Therefore, from (i),
t²-t=6
t²-3t+2t-6=0
t(t-3)+2(t-3)=0
Therefore, (t-3)(t+2)=0
Therefore, t=3 or t = -2
But,
![e^x =t](https://tex.z-dn.net/?f=e%5Ex%20%3Dt%20)
Therefore,
![e^x = 3](https://tex.z-dn.net/?f=e%5Ex%20%3D%203%20)
or
![e^x = -2](https://tex.z-dn.net/?f=e%5Ex%20%3D%20-2)
Taking ln on both sides,
Therefore,
![ln(e^x)=ln(3)](https://tex.z-dn.net/?f=ln%28e%5Ex%29%3Dln%283%29)
or
![ln(e^x) = ln(-2)](https://tex.z-dn.net/?f=ln%28e%5Ex%29%20%3D%20ln%28-2%29)
But natural log of negative numbers does not exist since negative numbers are not in the domain of ln(x)
Therefore,
![ln(e^x) = ln(-2)](https://tex.z-dn.net/?f=ln%28e%5Ex%29%20%3D%20ln%28-2%29)
is discarded
Therefore, x = ln(3) is the only solution.