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timama [110]
3 years ago
15

A line passes through the point (-3,6) and is parallel to the line with the equation y=

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

y=-4x-6

Step-by-step explanation:

y=-4x+5  m1=-4

m1=m2=-4 (the number near x is equal for the line and the searched line)

y=m2x+b

6=-4(-3)+b

b=-6

y=-4x-6

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Answer:

Step-by-step explanation:

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2 years ago
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A customer left a 15% tip for a meal that cost $64. What was the total amount the customer paid for the meal and tip?
Inessa05 [86]

Answer:

73.6

Step-by-step explanation:

64x15%=9.6

9.6+64=73.6

4 0
2 years ago
PLS HELP WILL GIVE BRAINLIEST :)
Rus_ich [418]

Step-by-step explanation:

the slope intercept form is

y = ax + b

"a" being the slope, "b" being the y- intercept (which is the y-value when x = 0).

the slope here :

in the table x is always increasing by 2.

and y is always investing by 1.

so, the slope is 1/2

the y-intercept :

we need to find the y-value for x = 0.

but we don't have a data point with x = 0 in the table.

so, we have to extend the structure of the table to the left.

x decreases by 2 (making it 0), and y decreases by 1 (making it -1).

therefore, the y- intercept (b) is -1.

and the line equation is

y = (1/2)x - 1

not sure about "the other method".

there is the point-slope form of the equation :

y - y1 = a(x - x1)

again with "a" begin the slope, and (x1, y1) being a point on the line.

if we get the y-intercept in the table, then this point is (0, y1).

and the equation would be

y - y1 = ax

in our case

y + 1 = (1/2)x

and another method ?

sometimes people write

nx + my = c

in our case starting with the original equation

y = (1/2)x - 1

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6 0
2 years ago
What 2 numbers multiply to -100 and add to -21 ​
mylen [45]

Answer:

-25 and 4

Step-by-step explanation:

-25×4=-100 and -25+4=-21

6 0
3 years ago
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A potential energy function is given by U = A x3 + B x2 − C x + D . For positive parameters A, B, C, D this potential has two eq
Ivenika [448]

Answer:

7.8655

Step-by-step explanation:

Given the functionl

U=Ax^3+Bx^2-cx+D

Where,

A=1.45J/m^3\\B=2.85J/m^2\\c= 1.7J/m\\D=0.6J

We have, replacing,

U=1.45x^3+2.85x^2-1.7x+0.6

We need to derivate and verify for stable equilibrum that,

\frac{d^2 U}{dx^2}>0

Then,

U'(x) = 4.32x^2+5.7x-1.7

Roots in,

x_1=-1.57008\\x_2=0.250636

We obtain U"(x), then we have

\frac{d^2U}{dx}=8.64x+5.7

For x=-1.57, U"(x)=-7.86549 Unestable

For x=0.250636 U"(x)=7.8655>0 Stable

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3 years ago
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