3 years ago

Question 1 of 25 f(x) = 2x2 + 6x - 4 g(x) = 5x3 - 6x? - 3 Find (f + g)(x).

Mathematics

1 answer:

Usimov [2.4K]3 years ago

4 0

Answer:

option B

Step-by-step explanation:

$f(x) = 2x^2 + 6x -4\\\\g(x) = 5x^3 - 6x^2 - 3\\\\(f + g)(x) = f(x) + g(x) \\\\$

$= (2x^2 + 6x - 4) + ( 5x^3 -6x^2 - 3) \\\\= 2x^2 + 6x - 4 + 5x^3 - 6x^2 - 3\\\\= 5x^3 + 2x^2 - 6x^2 + 6x - 4 - 3 \\\\= 5x^3 - 4x^2 + 6x - 7$

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A square has the same area as a rectangle whose

amid [387]

Answer:

C) 32 * 2**1/2

Step-by-step explanation:

For rectangle P = L + W = 24 but L = 2W so

2W + W = 24

3W = 24

W = 8 and L = 2W = 16

A = L * W = 16 * 8 = 128

SO for the square with the same area

A = L * L = 128

L**2 = 128

L = 8 * 2**1/2

P = 4L = 32 * 2**1/2

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3 years ago

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s2008m [1.1K]

S={ 11 12 13 14 15 16 17 18
21 22 23 24 25 26 27 28
31 32 33 34 35 36 37 38
41 42 43 44 45 46 47 48...
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3 years ago

24 and 25 thanksssssss

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24:D
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3 years ago

PLEASE HELP WITH THIS QUESTION!! DUE BY 1PM! wILL RATE YOU GOOD!! THANK YOU!!

kupik [55]

Find $a_{1}$ by plugging in 1 into n:
$a_{1} = 98-2(1)=96$

Find $a_{11$ by plugging in 11 into n:
$a_{11} = 98-2(11)$
$a_{1} =98-22=76$

Now to find the sum your formula is:
$S_{n} = \frac{n}{2} ( a_{1} + a_{n})$
$n = 11, a_{1} = 96 , a_{11} =76$

Now plug that into the formula
$S_{11} = \frac{11}{2} (96+76)$
$S_{11} = 5.5(172)=946$

Hope that helps

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3 years ago

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umka2103 [35]

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3 years ago

Question 1 of 25 f(x) = 2x2 + 6x - 4 g(x) = 5x3 - 6x? - 3 Find (f + g)(x).​

Question 1 of 25 f(x) = 2x2 + 6x - 4 g(x) = 5x3 - 6x? - 3 Find (f + g)(x).