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1 year ago

WHEN THE WHOLE IS THE SAME, HOW MANY 8THS DOES IT TAKE TO EQUAL 1\4. DRAW A MODEL TO SHOW YOUR ANSWER.

Mathematics

2 answers:

viktelen [127]1 year ago

8 0

It takes 2 eighths to equal 1/4
This is why:

Lostsunrise [7]1 year ago

7 0

Answer: 4

Step-by-step explanation:

4 times 2 is 8 if you make 4 eighths you will get 1/4 a

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What is 2/5 divided by -1/2 minus 3/2

shutvik [7]

Answer:

$- \frac{23}{10}$

Step-by-step explanation:

$\frac{2}{5} \div \frac{ - 1}{2} - \frac{3}{2}$

➡️ $- \frac{2}{5} \times 2 - \frac{3}{2}$

➡️ $- \frac{4}{5} - \frac{3}{2}$

➡️ $- \frac{23}{10}$

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2 years ago

Read 2 more answers

Does the equation y = 99x show a proportional relationship between x and y?

Naily [24]

Yes because it shows that y is proprtional equal to 99 times x. so whenever you need to work out y, you get x and times it by 99.

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3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

Yesterday morning, the temperature was -11. The temperature increased 7 by noon and then decreased 4 by nightfall. What was the

tamaranim1 [39]

Answer:

-8 is the answer

Step-by-step explanation:

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3 years ago

Sumaya is considering investing $8500 into the bank. Bank A offers 2.25% interest rate compounded semiannually. Bank B offers 1.

Harman [31]

The answer to your problem is B.

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2 years ago