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1 year ago

CAN SOMEONE PLEASE HELP ME???

Mathematics

1 answer:

Varvara68 [4.7K]1 year ago

5 0

Answer:

m=2

Step-by-step explanation:

slope is the average rate of change in a specific interval

we can calculate slope in this case with Δy/Δx or (y2-y1)/(x2-x1)

m=(y2-y1)/(x2-x1)

=(-1-7)/(-3-1)

=-8/-4

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Step-by-step explanation:

The formula for area is length multiplied by width

7 X 6 = 42

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2 years ago

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5. On a recent day, the exchange rate for US dollars to British pounds

attashe74 [19]

250*0.62= 155

155 pounds is your answer.

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2 years ago

Which is the factored form of 64p3 + 125?

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Answer:

q .no d

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64p^3+125

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2 years ago

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Help pleaseeeeeeeeeeeeeeee

kupik [55]

Answer:C

Step-by-step explanation:

your answer is 390

First area of the rectangle which formula is bxh base time height.

that gives you 300 since 15x20=300

The for the triangle Formula is Basexheight deivded by 2

so 15x12 devided by 2 =90

300+90=390

Hope this helps you. :)

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2 years ago

Travel time data is collected on an arterial. With 30 runs, an average travel time of 152 seconds is computed over the 2.0 miles

o-na [289]

Answer:

The 95% confidence bounds is $145.80 < \mu < 158.19$

It was not necessary to make any assumption about the shape of the travel time distribution

Step-by-step explanation:

From the question we are told that

The sample size is n = 30

The sample mean is $\=x = 152$

The standard deviation is $\sigma = 17.3 \ second$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{17.3 }{\sqrt{30} }$

=> $E = 6.19$

Generally 95% confidence bounds is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $152 -6.19 < \mu < 152 -6.19$

=> $145.80 < \mu < 158.19$

This 95% confidence bounds show that there is 95% confidence that the true mean lies within this bound hence there is it was not necessary to make any assumption about the shape of the travel time distribution

5 0

2 years ago