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hoa [83]
3 years ago
10

Which triangle is a 30°-60°-90° triangle?

Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer:

the first one

Step-by-step explanation:

Hey There!

Look at the image for the rule of a 30- 60 - 90 triangle

x = 5

the hypotenuse would be x2 so 10

the longer leg would be x\sqrt{3}

So the first triangle is the right answer

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Find the value of cos 28°​cos 62°​– sin 28°​sin 62°​
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<h2>Answer:</h2>

cos 28°​cos 62°​– sin 28°​sin 62°​ = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

<em>cos(A+B) = cosAcosB - sinAsinB             -----------------(i)</em>

We can apply such identity to solve the given expression.

<em>Given:</em>

cos 28°​cos 62°​– sin 28°​sin 62°​

<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>

A = 28°

B = 62°

<em>∴ Substitute these values into equation (i) to have;</em>

<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>

<em />

<em>Solve the left hand side.</em>

<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>

⇒ 0 = <em>cos28°cos62° - sin28°sin62°     (since cos 90° = 0)</em>

<em />

<em>Therefore, </em>

<em>cos28°cos62° - sin28°sin62° = 0</em>

<em />

<em />

8 0
3 years ago
Graph and solve the following system.<br><br><br> у= 2x + 3<br><br> y = -2x + 3
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graphed in the image attached with points,

hope this helps :D

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3 years ago
The running back for the Bulldogs football team carried the ball 5 times for a total loss of 8 3 4 yards. Find the average chang
aliya0001 [1]

Answer: The average change in field position on each run was 1\frac34 yards.

Step-by-step explanation:

Given: Total loss of field = 8\dfrac34 yards  = \dfrac{35}{5}\text{ yards}

Number of times football team carried the ball  = 5

The average change in field position on each run =  \dfrac{\frac{35}{4}}{5}

=\dfrac{35}{4\times5}\\\\=\dfrac{7}{4}\\\\=1\dfrac34 yard .

The average change in field position on each run was 1\frac34 yards.

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Answer: your answer is 3.

Step-by-step explanation:

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We want to factor the following expression:
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Answer:

We have \mathbf{U= 9x^3 \:and\:V=y+1}

Step-by-step explanation:

We want to factor the expression 81x^6-(y+1)^2 in the form of (U+V)(U-V)

We need to find U and V

We can use formula : a^2-b^2=(a+b)(a-b)

We can write 81x^6 as (9x^3)^2

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Applying formula: a^2-b^2=(a+b)(a-b)

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So, we have \mathbf{U= 9x^3 \:and\:V=y+1}

8 0
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