All categories

2 years ago

Help me pleaseeeeeeeeeeee

Mathematics

2 answers:

adell [148]2 years ago

7 0

Answer:

a. 87 b. 59

Step-by-step explanation:

typing bc I need to have 20 letters

Leya [2.2K]2 years ago

4 0

Answer:

Step-by-step explanation:

a) 6305/65= 97

b) 94+94= 188

306-188= 118

You might be interested in

Simplify (2x+1)^2<br><br><br><br>what is the answer?

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

4x^2+4x+1

3 0

3 years ago

Read 2 more answers

Write an equation that could be used to find the value of x using the interior angles of ∆BDC, then solve it.

Alecsey [184]

9514 1404 393

Answer:

x = 16

Step-by-step explanation:

Either or both of the right triangles can be used to find x. Or, triangle ABC could be used. All numbers are assumed to be degrees.

<u>Using ∆ABD</u>

55 +90 +2x+3 = 180

2x = 32 . . . . . . subtract 148

x = 16

<u>Using ∆BCD</u>

50 +90 +2x+8 = 180

2x = 32 . . . . . . subtract 148

x = 16

<u>Using ∆ABC</u>

55 +(2x +3) +50 +(2x +8) = 180

4x = 64 . . . . . . . subtract 116

x = 16

6 0

3 years ago

Sarah bought 3 pounds of apples for $6 . How much did each pound of apples cost ?

viva [34]

Answer:

Step-by-step explanation:

6/3 = 2

6 0

3 years ago

for some reason brainly deleted this for not being "school related" even though it is so here's a repost, can anyone help me wit

tangare [24]

Answer:

1 tenth and 9 hundreds

Step-by-step explanation:

Ok so this is not a gud explanation but believe me that answer is correct

a tenth is 10% out of a hundred so thats 10/100 and since the 9 hundreds is already there 10/100+ 9/100= 19/100

Hope you have a gud day :)

6 0

2 years ago

If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,

julsineya [31]

<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

$\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)$

$(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166$

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0

3 years ago