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SVETLANKA909090 [29]
2 years ago
14

Help me pleaseeeeeeeeeeee

Mathematics
2 answers:
adell [148]2 years ago
7 0

Answer:

a. 87 b. 59

Step-by-step explanation:

typing bc I need to have 20 letters

Leya [2.2K]2 years ago
4 0

Answer:

Step-by-step explanation:

a) 6305/65= 97

b) 94+94= 188

   306-188= 118

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3 years ago
joel has 24 sports trophies. of the trophies, 1/8 are soccer trophies. how many soccer trophies does joel have?
hichkok12 [17]

Answer:

3 soccer trophies does Joel have

Step-by-step explanation:

As per the statement:

Joel has 24 sports trophies.

⇒Total sport trophies Joel have= 24

It is also given: of the trophies, 1/8 are soccer trophies

We have to find how many soccer trophies does Joel have.

\text{Joel have soccer trophies} =\frac{1}{8} \cdot 24

Simplify:

\text{Joel have soccer trophies} =3

Therefore, 3 soccer trophies does Joel have

3 0
3 years ago
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Galina-37 [17]

Answer:

First blank - <em><u>SSS</u></em><em><u> </u></em>congruent condition

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5 0
3 years ago
Read 2 more answers
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
Summer day camp is about to begin. Today there are 132 boys signed up and 219 total children signed up. How many more than girls
Aleks04 [339]
To find the number of girls signed up for camp, we just subtract the number of boys from to total number of children. There are 132 boys and 219 children, which gives us

219 - 132 = 87 girls. To find how many boys there are than girls, we just find the difference between the 132 boys and 87 girls by subtracting again:

132 - 87 = 45 more girls than boys.
6 0
3 years ago
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