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leonid [27]
3 years ago
11

Which of these items is a tax form that employers send to their employees? W–2 form 1040EZ form tax schedule form

Mathematics
2 answers:
lesantik [10]3 years ago
6 0

Answer:

W-2

Step-by-step explanation:

Each year employers are required to send out W-2 forms to all employees stating the amount they earned and all of the withholdings from their salary, such as federal tax, state tax, retirement, health insurance, etc.

Kamila [148]3 years ago
4 0

Answer:

W–2 form is the correct answer.

Step-by-step explanation:

The W-2 form is a form that is required by every employer for his employees. The employer needs to send these forms to his employees and the Internal Revenue Service (IRS) at the end of the year. This form contains details of the employee's salaries and their tax deductions from salaries.

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(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^
Sedbober [7]
Hello,

a)
I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\

= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\

=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\

= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\
= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\


I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\
I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\


b)
\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\
= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\
= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\






\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\
= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\







c)

I_n=  \dfrac{n-1}{n} * I_{n-2} \\

I_{2n+1}=  \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\
= \dfrac{2n}{2n+1} * I_{2n-1} \\
= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\
= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\

I_1=1\\






3 0
3 years ago
Simplify the expression for the area
larisa86 [58]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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3 years ago
Profit is the amount of money that remains after all expenses of a project have been paid. The year has just​ ended, and Ajax​ C
lilavasa [31]

Answer:

the Profit earned by the company is $280,489

Step-by-step explanation:

Total Cost of 5 projects awarded = $7,435,000

Cost of Project​ 1 = $1,245,000

Cost of Project​ 2 = $985,689

Cost of  Project​ 3 = $1,723,000

Cost of Project​ 4 = $2,567,054

Cost of Project​ 5 = $633,768

We need to find the profit earned by the company.

First we need to find Total cost spent on all 5 projects.

It can be found by adding cost spent on all projects.

Total cost spent on all 5 projects = Cost of Project 1 + Cost of Project 2 + Cost of Project 3 + Cost of Project 4 + Cost of Project 5

Total cost spent on all 5 projects = $1,245,000+ $985,689 + $1,723,000+ $2,567,054 + $633,768

Total cost spent on all 5 projects = $7,154,511

Now we can calculate profit earned using formula:

Profit earned = Total Cost of 5 projects awarded - Total cost spent on all 5 projects

Profit earned = $7,435,000 - $7,154,511

Profit earned = $1,280,489

So, the Profit earned by the company is $280,489

6 0
3 years ago
3. I opened a compound interest account with $300 at 2%. How much money will be in the
MArishka [77]

Answer:

there will be 408$ at the end of 18 months

Step-by-step explanation:

2% of 300 is 6 and 6 x 18 = 108. 108 + 300 = 408

8 0
3 years ago
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