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8090 [49]
2 years ago
14

pls help Using the pattern learned for the square of a binomial, square (3x-5y^2) Explain the pattern.

Mathematics
1 answer:
Bess [88]2 years ago
6 0

Step-by-step explanation:

The binomial square product states that

(x  -  y) {}^{2}  = x {}^{2}   -  2xy +  {y}^{2}

So this means

If there a coefficient in front of x are y, we multiple them as well.

In terms, this means that a binomial squared is equal to

The first term squared + the two terms multiplied together and by 2 + the last term squared.

(3x - 5y {}^{2} ) {}^{2}  = 9 {x}^{2}  - 30xy {}^{2}  + 25 {y}^{4}

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CHOOSING BRAINLIEST ( SCREENSHOT PROVIDED )
Westkost [7]

Answer:

y= 25

i think

Step-by-step explanation:

3 0
3 years ago
3 times a number is 54 less than the square of that number. Find the positive solution.
OlgaM077 [116]

Answer:x=9

Step-by-step explanation:

To find the positive solution for this, then we will say;

Let the number be x

3x<x^2-54

x^2-3x-54<0

Then we are going to factorise

x^2-9x+6x-54=0

(x^2-9x)+(6x-54)=0

x(x-9)+6(x-9)=0

(x+6)(x-9)=0

Therefore, The positive solution for this is: x=9

4 0
3 years ago
I need help can somebody help me please???
stich3 [128]
What’s your question ?
3 0
2 years ago
Given the relation (2,3), (4,7), (6,11), (x,3), which of the following values of x will make the relation function
Elan Coil [88]
As you said, (x,3) = (2,3)
So x = 2

Thank you very much.
5 0
2 years ago
Help me simplify this, please!!
OlgaM077 [116]
- \sqrt[3]{2 x^{4} y^{2}  } *3 \sqrt[3]{20 x^{5}y } =-3  \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} =  \\ \\ =-3 \sqrt[3]{40 x^{9}  y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9}  y^{3}  } = \\  \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} }  \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}
Answer: B.
6 0
3 years ago
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