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Kazeer [188]
3 years ago
13

A mountain road is 5 miles long and gains elevation at a constant rate. After 2 miles, the elevation is 5500 feet above sea leve

l. After 4 miles, the elevation is 6200 feet above sea level.
What would be the equation of this line?

Find the elevation of the road at the point where the road begins.


Describe where you would see the point in part (a) on a graph where represents the elevation in feet and represents the distance along the road in miles.

Mathematics
2 answers:
stealth61 [152]3 years ago
5 0

Answer:

I hope this helps

Step-by-step explanation:

denis-greek [22]3 years ago
4 0
I really need points so I comment sorry I don’t know the answer
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Which method would be more efiicient to solve the system y=1/2x and 2x+3y=28
Licemer1 [7]
Probably the subsitution method


y=1/2x
subsitute that fr y

2x+3(1/2x)=28
2x+3/2x=28
times 2 both sides
4x+3x=56
7x=56
divide by 7 both sides
x=8
sub back

y=1/2x
y=1/2(8)
y=4

(x,y)
(8,4)
6 0
3 years ago
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
X+3/2=6 linear equations
Gre4nikov [31]

Answer:

x=9

Step-by-step explanation:

Multiply both sides by 2.

x+3= 12

Subtract both sides by 3.

x=12-3

x=9

4 0
3 years ago
How many times does 50 go into 70
elena55 [62]
One time because 50 x 50 equals 100 and that to large
4 0
3 years ago
Read 2 more answers
Write an expression for this one <br> the sum of an odd integer and the next odd integer.
Sidana [21]
Let x is the odd integer
x +2 is the next odd integer
so sum of an odd integer and the next odd integer:
x + (x+2) 
8 0
3 years ago
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