Given that mean of quiz scores = 6.4 and standard deviation = 0.7
And we need to use Chebyshev's theorem to find the range in which 88.9% of data will reside.
Chebyshev's theorem states that "Specifically, no more than 
of the distribution's values can be more than k standard deviations away from the mean".
That is 
k = 3
So, we want the range of values within 3 standard deviations of mean.
Hence range is [mean -3*standard deviation, mean +3*standard deviation]
= [6.4 - 3*0.7 , 6.4+3*0.7]
= [6.4 - 2.1 , 6.4+2.1] = [4.3,8.5]
Since all angles in a triangle are equal to 180 and you already have two angles you just have to subtract.
So, 180-(65 + 45)
Simplify = 180- 110
Equals = 70
Answer:
Step-by-step explanation:
Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
For a random single taxi std deviation is 2.20
But for a sample of size 10, std deviation would be
This would be less than the 2.20
Because std devition is less for sample we get a big z score for the sample than the single.
As positive values of z increase we find that probability would decrease since normal curve is bell shaped.
So single taxi fare would have higher probability than sample.
B) Here >24.
By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10
The answer should be B) if my math is correct
So because trail Y has a negative slope, and X is perpendicular to Y the X has a positive slope. \ <---- neg slope y and / <----- pos slope x
