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sladkih [1.3K]
3 years ago
15

Pls help I’ll mark u if ur right

Mathematics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

dividing by 1000

Step-by-step explanation:

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(15y^0 x^-3 z^2/ 3x^3 y^7 z^1/2)^2
ArbitrLikvidat [17]
Hello! For this you are just going to do this step by step, and remember to use PEMDAS. That is the order in which you should do the math. The abbreviation stands for  Parenthesis, exponents, multiplication, division, addition and subtraction. So lets get started!
<span><span>(<span><span><span><span>(<span><span><span><span><span>15<span>y0</span></span><span>x<span>−3</span></span></span><span>z2</span></span>3</span><span>x3</span></span>)</span><span>(<span>y7</span>)</span></span><span>z1</span></span>2</span>)</span>2</span><span>=<span><span><span>254</span><span><span><span>x6</span><span>y14</span></span><span>z6</span></span></span><span>x6</span></span></span><span>=<span><span>254</span><span><span>y14</span><span>z6</span></span></span></span>

Hope this helps!! If you need any more help or further explanation just let me know!! :)
 

6 0
3 years ago
How do I do this problem???
Andreas93 [3]
A. there are 72 right-handed batters. this is what you do:
5:8
45:?
45/5=9
8*9=72 so
45:72 
b. there are 45 left-handed batters
the total batters is 45+72=117
so the ratio of left-handed to the total batter would be 45:117
hope this helps :)

4 0
3 years ago
Part A: If (7^2)^x = 1, what is the value of x? Explain your answer. (10 points)
Alex777 [14]
Answers:Part A: The value of x is 0.Part B: X can be any real number.
In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.
In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.
Therefore any number will work in Part B.

3 0
3 years ago
When the solutions are going to be complex, which methods can be used to solve quadratic equations?
yKpoI14uk [10]
You could complete the square to state the vertex. 
You could use the quadratic equation to find the roots (which are complex). 

Try an example that will require both.

y = x^2 + 2x + 5

Step One
Get the graph. That's included below.

Step Two
Provide the steps for completing the square.
Note: we should get (-1,4)

y= (x^2 +2x ) + 5
y = (x^2 +2x + 1) + 5 - 1
y = (x +1)^2 + 4

The vertex is at (-1,4)

Step Three
Find the roots. Use the quadratic equation. Note that the graph shows us that the equation never crosses or touches the x axis. The roots are complex.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 2
c = 5

\text{x = }\dfrac{ -2 \pm \sqrt{2^{2} - 4*1*5 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{4 - 20 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{-16 } }{2}
\text{x = }\dfrac{ -2 \pm 4i }{2}
x = -1 +/- 2i

x1 = -1 + 2i
x2 = -1 - 2i And we are done.


7 0
3 years ago
What is the GCF of 60 and 24
Nadusha1986 [10]
Though there are many common factors of 24, 36, and 60, thegreatest common factor (GCF) of 24, 36, and 60 is 12.
5 0
3 years ago
Read 2 more answers
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