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3 years ago

13

How do get 423 from the numbers 100, 50, 75, 3, 10 & 7?

2 answers:

PilotLPTM [1.2K]3 years ago

5 0

100 + 100 + 50 +50 + 50 + 50 + 10 + 7 + 3 + 3

Rudik [331]3 years ago

4 0

423 = 100 + 100 + 100 + 100 + 10 + 10 + 3

hope this helps

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Hi i need help below thank you 32 POINTS

lara [203]

A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5

A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==

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2 years ago

Help plzzzz Which equation describes the statement shown?

Sedaia [141]

Answer:

y=x-3

Step-by-step explanation

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3 years ago

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The Sugar Sweet Company is going to transport its sugar to market. It will cost $7500 to rent trucks, and it will cost an additi

Inga [223]

<span>Let C represent the total cost (in dollars),
and let S represent the amount of sugar (in tons) transported

equation:
C(s) = </span><span>225s + 7500

</span><span>find the total cost to transport 11 tons of sugar.
</span>C(11) = 225(11) + 7500
C(11) = 2475 + 7500
C(11) = 9975

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7 0

2 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

3 0

3 years ago

Write this number using digits:

Setler [38]

Answer: 454,000,004,542

5 0

2 years ago

Read 2 more answers