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Pani-rosa [81]
3 years ago
7

To find the average rate (speed) of a car traveling on a highway, the distance traveler is divided by the time: R=D/T. If the di

stance is D=36/x^2-36 miles and the time is T=6x^2+6x/x^2+7x+6 hours, find a simplified expression for the average rate of the car.
a) 1/x
b) 6/x-6
c) 6/x^2-6x
d) 1/x^2-6x
Mathematics
1 answer:
RSB [31]3 years ago
5 0

Answer:

It's C

Step-by-step explanation:

Just took the quiz and got it right.

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Use the substitution method to solve the given system of equations. Write your answer as an ordered pair, (x, y).
Gnoma [55]

Answer:

(-3, -2)

Step-by-step explanation:

Look at the second equation, we can easily rearrange it to make x the subject.

x - 4y = 5

x = 4y + 5

Now lets put that into the second equation

2x - 2y = -2

2(4y + 5) - 2y = -2

6y + 10 = -2

6y = -12

y = -2

Now lets find x!

x = 4y + 5

x = 4(-2) + 5

x = -3

Now lets format the answer like the question says (ordered pair)

(-3, -2)

Recap: We used substitution and made an equation to work out one of the variables first, then found the second variable using the first.

3 0
3 years ago
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100 students attended a revision lesson at the weekend.
solniwko [45]

Answer:

I am pretty sure its 30 students

4 0
3 years ago
Which multiplication problem is equivalent to 338÷34?
gtnhenbr [62]

Answer:

What are the options?

Step-by-step explanation:

7 0
3 years ago
Select two ratios that are equivalent to 7: 10
hammer [34]
21:30 and 35: and 50 this is because 7 times 3 is 21, 10 times 3 is 30, and 7 times 5 is 35, and lastly 10 times 5 is 50
4 0
3 years ago
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I need help with this please :)
Marina CMI [18]

9514 1404 393

Answer:

  all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

  \dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}

4 0
3 years ago
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