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adelina 88 [10]
3 years ago
6

Please help need this done by tomorrow thank you [PHOTO]​

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
6 0

Answer:

Step-by-step explanation:

The two angles must add to 180

(4x-2)+(3x+14)=180

7x+12=180

7x=168

x=24

scZoUnD [109]3 years ago
6 0
X = 24 is your answer
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Tell whether it is possible to draw a triangle with the given side lengths. 4 cm, 4 cm, 7 cm
Sati [7]
Yes it is because 4+4=8 and 8 is larger than 7
5 0
2 years ago
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A house cat weighs 9.22 pounds Hercules the liger is the worlds largest cat and weighs 100 times the weight of the house cat how
Tanya [424]

Answer:

922 pounds

Step-by-step explanation:

9.22 x 100 = 922

5 0
3 years ago
Use function notation to write a recursive formula to represent the sequence: 3, 6, 9, …
dlinn [17]

Answer:

f(n) = f(n - 1) + 3

Step-by-step explanation:

Substitute $ n = 1, 2, 3,.. $ to get the recursive formula.

OPTION 1: f(n) = f(n - 1) + 3

Substituting n = 1.

f(1) = f(1 - 1) + 3 = 0 + 3 = 3.

Substituting n = 2.

f(2) = f(2 - 1) + 3 = f(1) + 3 = 3 + 3 = 6.

Substituting n = 3.

f(3) = f(3 - 1) + 3 = f(2) + 3 = 6 + 3 = 9.

The numbers match the given sequence. So, we say the above recursive formula represents the sequence.

OPTION 2: f(n) = f(n - 1) + 2

Substituting n = 1

f(1) = f(0) +  2 $ \ne $ 3.

So, this is eliminated.

Similarly, OPTION 3 and OPTION 4 can be eliminated as well.

4 0
3 years ago
Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

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Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


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A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
3 years ago
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Oksana_A [137]

Answer:

Step-by-step explanation:

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34 quarter is  = 8.50

1.70 plus 8.50 plus 4.90 = 15.1 i think

7 0
3 years ago
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