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Sophie [7]
3 years ago
8

The table of paired values represents a proportional relationship.

Mathematics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

8

Step-by-step explanation:

You might be interested in
Solving by elimination <br> -6x+6y=6 -6x+3y=-12
labwork [276]
So elimination method is basically adding the equations and canceling out variables. 
-6x + 6y = 6
-6x + 3y = -12
The eaiest way to solve is by multiplying the bottom equation by -1.
-6x + 6y = 6
 6x - 3y = 12
Now you add the eqautions.
3y = 18
Divde 3 from both sides.
y = 6
Now plug in 6 into any of the original two equations. Lets use the first one.
-6x + 6(6) = 6
-6x + 36 = 6
Subtract 36 from both sides.
-6x = -30
Divide -6 from both sides.
x = 5
So your solution is (5, 6).
I hope this helps love! :)
8 0
3 years ago
What is the solution 5x-15=-25
IRISSAK [1]

Answer:

x= -2

Step-by-step explanation:

MARK AS BRAINLIEST!!

4 0
3 years ago
Read 2 more answers
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
131.049- 82.604rounded to the nearest whole number
Sergeeva-Olga [200]
48 is the answer.I hope this helps
5 0
3 years ago
CAN SOMEONE HELP ME PLEASE ASAP!?
GalinKa [24]

Answer:

true

Step-by-step explanation:

the lines of the new shape are parallel to the lines of the original shape, there seems to be the same scaling factor for all sides and all "projection" lines BB' and CC' cross at A, which is also A' Ave the center of the dilation.

5 0
2 years ago
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