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avanturin [10]
3 years ago
5

Triangle ABC has a perimiter of 22cm AB=8cm BC=5cm by calculation deduce whether triangle ABC is a right-angled triangle

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0

Answer:

ABC is not a right triangle  

Step-by-step explanation:

The computation is shown below:

AC is

= Perimeter - (AB + BC)

= 22 - (8+5)

= 22 - 13

= 9

Now  

= 9^2 + 13^2

= 81 +169

= 250

And, the perimeter is  

= 22^2

= 484

Since the amount are not equivalent therefore ABC is not a right triangle  

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17+p=7p-13 Plz help me asap
Hunter-Best [27]

First you had to subtract by seventeen from both sides of equation form.

17+p-17=7p-13-17

Then simplify.

p=7p-30

Next, subtract by seven-p from both sides of equation form.

p-7p=7p-30-7p

Simplify.

-6p=-30

Then you divide by negative six from both sides of equation form.

\frac{-6p}{-6}= \frac{-30}{-6}

And finally, simplify by equation.

-30/-6=5

Final answer: \boxed{p=5}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie


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The ELISA test was an early test used to screen blood donations for antibodies to HIV. A study (Weiss et al. 1985) found that th
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Answer:

0.057258

Step-by-step explanation:

From the statement of the problem, the following information were given:

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The following can be derived:

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We are to determine the probability that a person has HIV given that they test positive. [P(HIV|Positive)]

Using Baye's theorem for Conditional Probability

P(HIV|Positive)=\dfrac{P(Positive|HIV)P(HIV)}{P(Positive|HIV)P(HIV)+P(Positive|No HIV)P(No HIV)}=\dfrac{0.979*0.005}{0.979*0.005+0.081*0.995}

P(HIV|Positive)=0.057258

The probability that a random person tested has HIV given that they tested positive is 0.057258.

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Step-by-step explanation:

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