Addition of 6q + 1 and q + 11 is 7q + 12
<em><u>Solution:</u></em>
Given that, we have to add the given two expressions
<em><u>Given expressions are:</u></em>
6q + 1 and q + 11
We have to add both the expressions
Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11
Add the coefficients of same variable. Here "q" is present in two terms
Therefore, add 6q and q
Similarly, add the constants 1 and 11
<em><u>Thus finally addition is done as:</u></em>

Thus addition of 6q + 1 and q + 11 is 7q + 12
ANSWER

EXPLANATION
The given equation is

Take antilogarithm of both sides to base e.

This will simplify to

Group like terms to obtain,


Take square root of both sides to get,
P=2/3 the math is in the picture ☺️
Answer:

Step-by-step explanation:
slope-intercept form: y = mx + b
Given:
Slope(m) = 
Point = (-1, 3)
To write the equation in slope-intercept form we need to know the slope(m) and the y-intercept(b). Since we already know the value of m, we can use it and the given point to find b:



Now that we know the values of b and m, we can write the equation:
