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2 years ago

13

Consider the reduction of the complex figure with a scale factor of 1

2 answers:

BlackZzzverrR [31]2 years ago

6 0

Answer:

a

Step-by-step explanation:

STALIN [3.7K]2 years ago

3 0

It’s A here’s a picture to make you happy so yeah

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Shkiper50 [21]

Negative six sevenths -6/7

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2 years ago

The number of airline passengers in 1990 was 466 million. The number of passengers traveling by airplane each year has increased

taurus [48]

Answer:

2010.

Step-by-step explanation:

We have been given an exponential growth formula $P(t)=466\cdot 1.035^t$ , which represents number of passengers traveling by airplane since 1990.

To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:

$900=466\cdot 1.035^t$

$\frac{900}{466}=\frac{466\cdot 1.035^t}{466}$ $1.9313304721030043=1.035^t$

Take natural log of both sides:

$\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)$

Using property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)$

$0.658209129198=t\cdot 0.034401426717$

$\frac{0.658209129198}{0.034401426717}=\frac{t\cdot 0.034401426717}{0.034401426717}$

$19.1331927775=t\\\\t=19.1331927775$

This means that in the 20th year since 1990, 900 million passengers would travel by airline.

$1990+20=2010$

Therefore, 900 million passengers would travel by airline in 2010.

6 0

2 years ago

Find the absolute and local maximum and minimum values ofÂ fÂ . (Enter your answers as a comma-separated list. If an answer does

larisa86 [58]

Answer:

f(t)=4cos(t),Â â3Ï/2â¤tâ¤3Ï/2

Step-by-step explanation:

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2 years ago

Prove: If C⊂A and D⊂B then D−A⊂B−C

nalin [4]

Let $x\in D\setminus A$ , so that $x\in D$ but $x\not\in A$ . Since $D\subset B$ , it follows that $x\in B$ , and since $C\subset A$ , it follows that $x\not\in C$ , which means $x\in B\setminus C$ .

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2 years ago

If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will

aleksandrvk [35]

Answer:

$P(T\ n\ S) = \frac{1}{14}$

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

$Total = 4 + 5 + 3 + 3$

$Total = 15$

Represent the triangle with T and square with S

So, we're solving for P(T n S)

$P(T\ n\ S) = P(T) * P(S)$

Solving for P(T)

$P(T) = \frac{n(T)}{Total}$

$P(T) = \frac{5}{15}$

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

$P(S) = \frac{n(S)}{Total}$

$P(S) = \frac{3}{14}$

Recall that

$P(T\ n\ S) = P(T) * P(S)$

$P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}$

$P(T\ n\ S) = \frac{15}{15 * 14}$

$P(T\ n\ S) = \frac{1}{14}$

Hence, the required probability is

$P(T\ n\ S) = \frac{1}{14}$

3 0

2 years ago