M= QZ/Q-Z Ihope this helps
if the diameter of the can is 6 cm, then its radius is half that, or 3 cm.
![\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=3\\ h=12 \end{cases}\implies SA=2\pi (3)(12+3) \\\\\\ SA=6\pi (15)\implies SA=90\pi \implies SA\approx 282.74](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsurface%20area%20of%20a%20cylinder%7D%5C%5C%5C%5C%20SA%3D2%5Cpi%20r%28h%2Br%29~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%20%5Ccline%7B1-1%7D%20r%3D3%5C%5C%20h%3D12%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D2%5Cpi%20%283%29%2812%2B3%29%20%5C%5C%5C%5C%5C%5C%20SA%3D6%5Cpi%20%2815%29%5Cimplies%20SA%3D90%5Cpi%20%5Cimplies%20SA%5Capprox%20282.74)
In order to assess each of the deals equally, one has to know the price per yard of the given items.
1. 6.5 square yards for 6.26
n1 = 6.26 / 6.5 square yards
n1 = 0.963/square yard
2. 4 square yards for 3
n2 = 3/4 square yards
n2 = 0.75/square yard
3. 8.5 square yards for 8.1
n3 = 8.1/8.5 square yards
n3 = 0.953/square yards
4. 6 square yards for 7.2
n4 = 7.2/6 square yards
n4 = 1.2/square yard
From least to greatest the order would be 2,3,1, and 4.