Three consecutive even numbers add up to a number between 100 and 120 what might the number be?
1 answer:
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Answer:
h(2)+g(2) = -3
Step-by-step explanation:
Replace the variable (t) with (
2) in the expression.
h (2) = 3 - 5
Replace the variable (t) with (
2) in the expression.
g(2) = 2(2) -5
Replace the function designators in h(2) +g(2) with the actual functions.
h(t) = 3 - 5 +2 (2) ← plug h(2) into 2(t)
Remove parentheses.
3 - 5 + 2(2)
Multiply 2 by 2
3 - 5 + 4 - 5
Subtract 5 from 3
.
-2 + 4 - 5
Add -2 and 4
2 - 5
Subtract 5 from 2
-3
