20 POINTS!!!

Mathematics

1 answer:

Over [174]3 years ago

6 0

Answer:

you should put 20 points if you answer the question+ brainliest. if you dont people will think its free for example. I have a question you can answer to get your points back, just say something random. Sorry I couldnt help you but thanks for the points.

Step-by-step explanation:

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What is the value of the expression: 2 - (3x + 5y) if x = -3 and y = 4?

WARRIOR [948]

<h3>Hello there today we will solve your problem</h3>

here is our equation,

$2-(3x+5y)$ ,

Now we will plug in our numbers

__________________

${\boxed{x=-3}}$
${\boxed{y=4}$

__________________

$2-(3\cdot-3+5\cdot4)$

simplify it and we get

$2-(-9+20)$

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1. Simplify. 5–1(3–2)

konstantin123 [22]

Answer with explanation:

Using following law of indices

$1.x^a \times x^b=x^{a+b}\\\\2. (x^m)^n=x^{mn}\\\\ 3. x^{-n}=\frac{1}{x^n}\\\\4. \frac{x^m}{x^n}=x^{m-n}$

$1.5^{-1}\times 3^{-2}=\frac{1}{5}\times\frac{1}{3^2}\\\\=\frac{1}{5\times9}\\\\=\frac{1}{45}\\\\2. \frac{mn^{-4}}{p^0*q^{-2}}=\frac{mq^2}{n^4}\\\\ 3.0.0042=4.2\times 10^3\\\\4.6.12 \times 10^3=6.12 \times 1000=6120\\\\ 5.0.5 \times(8\times10^5})=\frac{1}{2}\times8 \times 10^5=4\times 10^5\\\\6. (9 \times 10^3)^2=9^2 \times (10^3)^2=81 \times 10^6\\\\7.( \frac{1}{2}a^{-4}\times b^2 )_{a=-2,b=4}{\text{or}}( \frac{1}{2}a^{4}\times b^{-2} )_{a=-2,b=4}=\frac{1}{2}\times (-2)^{-4}\times(4)^2{\text{or}}=\frac{1}{2}\times (-2)^{4}\times(4)^{-2}=\frac{16}{2\times16}=\frac{1}{2}$

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