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alekssr [168]
2 years ago
9

Verify that the indicated family of functions is a solution of the given differential equation. Assume an appropriate interval I

of definition for each solution.
d^2y/ dx^2 − 6 dy/dx + 9y = 0; y = c1e3x + c2xe3x When y = c1e3x + c2xe3x,
Mathematics
1 answer:
Rufina [12.5K]2 years ago
3 0

<em>y''</em> - 6<em>y'</em> + 9<em>y</em> = 0

If <em>y</em> = <em>C₁ </em>exp(3<em>x</em>) + <em>C₂</em> <em>x</em> exp(3<em>x</em>), then

<em>y'</em> = 3<em>C₁ </em>exp(3<em>x</em>) + <em>C₂</em> (exp(3<em>x</em>) + 3<em>x</em> exp(3<em>x</em>))

<em>y''</em> = 9<em>C₁ </em>exp(3<em>x</em>) + <em>C₂</em> (6 exp(3<em>x</em>) + 9<em>x</em> exp(3<em>x</em>))

Substituting these into the DE gives

(9<em>C₁ </em>exp(3<em>x</em>) + <em>C₂</em> (6 exp(3<em>x</em>) + 9<em>x</em> exp(3<em>x</em>)))

… … … - 6 (3<em>C₁ </em>exp(3<em>x</em>) + <em>C₂</em> (exp(3<em>x</em>) + 3<em>x</em> exp(3<em>x</em>)))

… … … + 9 (<em>C₁ </em>exp(3<em>x</em>) + <em>C₂</em> <em>x</em> exp(3<em>x</em>))

= 9<em>C₁ </em>exp(3<em>x</em>) + 6<em>C₂ </em>exp(3<em>x</em>) + 9<em>C₂ x</em> exp(3<em>x</em>))

… … … - 18<em>C₁ </em>exp(3<em>x</em>) - 6<em>C₂</em> (exp(3<em>x</em>) - 18<em>x</em> exp(3<em>x</em>))

… … … + 9<em>C₁ </em>exp(3<em>x</em>) + 9<em>C₂</em> <em>x</em> exp(3<em>x</em>)

= 0

so the provided solution does satisfy the DE.

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Varvara68 [4.7K]
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5 0
3 years ago
How do i write an exponential equation with a vertical asymptote other that y=0
antiseptic1488 [7]
Lets say we have
P(x)/q(x)

vertical assymtotes are in the form x=something, not y=0
y=0 are horizontal assemtotes


so verticall assymtotes
reduce the fraction
set the denomenator equal to zero
those values that make the deomenator zero are the vertical assymtotes

the horizontal assymtote
when the degree of P(x)<q(x), then HA=0

when the degree of P(x)=q(x), then divide the leading coefient of P(x) by the leading coeficnet of q(x)
example, f(x)=(2x^2-3x+3)/(9x^2-93x+993), then HA is 2/9





ok so for vertical assymtote example
f(x)=x/(x^2+5x+6)
the VA's are at x=-3 and x=-2

horizontal assymtote
make degree same
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6 0
3 years ago
Ms. Lee wrote a test with 15 multiple choice short answer questions. The multiple choice questions x are worth 5 points and the
hram777 [196]

x + y = 15 and 5x + 10y = 100 are the system of equations that represent this situation

<em><u>Solution:</u></em>

Let "x" be the number of multiple choice questions

Let "y" be the number of short answer questions

Worth of 1 multiple choice questions = 5 points

Worth of 1 short answer question = 10 points

<em><u>Ms. Lee wrote a test with 15 multiple choice short answer questions</u></em>

Therefore,

number of multiple choice questions + number of short answer questions = 15

x + y = 15 -------- eqn 1

<em><u>The maximum number of points possible on the test is 100</u></em>

Therefore, we frame a equation as:

number of multiple choice questions x Worth of 1 multiple choice questions + number of short answer questions x Worth of 1 short answer question = 100

x \times 5 + y \times 10=100

5x + 10y = 100 ------- eqn 2

Thus eqn 1 and eqn 2 are the system of equations that represent this situation

6 0
2 years ago
The numbers on this ruler represent centimeters. What is the precision of this ruler? cm What is the greatest possible error for
Leya [2.2K]

Answer:

1)0.1cm

2)0.05cm

3)1.65cm

4)1.75cm

Step-by-step explanation:

6 0
2 years ago
After dis if you get the answer right you get 50 points
svetoff [14.1K]

Answer:

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Step-by-step explanation:

First you have 24-(5+9)/2

So do 5+9=14

24-14=10

10/2=5

answer is 5

7 0
2 years ago
Read 2 more answers
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