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sladkih [1.3K]
3 years ago
14

Give a solution to the inequality x > 1. How many total solutions does it have?

Mathematics
1 answer:
fiasKO [112]3 years ago
7 0
I believe Infiniti because x is bigger then one and there are many many numbers bigger then one.
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Word form for (3 x 10)+ (7 x 1) + (3 x 1/10+(5 x1/100)
noname [10]

Three times ten plus seven times one plus three times one-tenth plus five times one-hundredth

4 0
3 years ago
Read 2 more answers
K-3k²-3k+2k²<br><br><br>what is the answer<br>please help me​
laiz [17]

Answer:

Assuming you want to simplify the expression, it can be shortened to:

-k² - 2k

Step-by-step explanation:

What you need to do here is called grouping like terms.  Like terms can be described as terms that have the same factors.  In this case, the factors we're looking at are k and k²:

Given:

k - 3k² -3k + 2k²

We'll rearrange to group like expressions:

= -3k² + 2k² + k -3k

Pull out common factors:

= (-3 + 2)k² + (1 - 3)k

And simplify:

= -k² - 2k

5 0
2 years ago
Consider the following pair of equations: −x − y = −5 y = x + 1 If the two equations are graphed, at what point do the lines rep
Mnenie [13.5K]
-x - y = -5
y = x + 1

-x -(x + 1) = -5
-x - x - 1 = -5
-2x = -5 + 1
-2x = -4
x = -4/-2
x = 2

y = x + 1
y = 2 + 1
y = 3

solution is : (2,3)
6 0
3 years ago
Consider the half of the sphere of radius 2 centered at the origin which lies above the xy-plane (a hemisphere). Suppose the den
Harlamova29_29 [7]

Answer:

25.133 units

Step-by-step explanation:

Since the density ρ = r, our mass is

m =  ∫∫∫r³sinθdΦdrdθ. We integrate from θ = 0 to π (since it is a hemisphere), Φ = 0 to 2π and r = 0 to 2  and  the maximum values of r = 2 in those directions. So

m =∫∫[∫r³sinθdΦ]drdθ      

m = ∫[∫2πr³sinθdθ]dr     ∫dФ = 2π

m = ∫2πr³∫sinθdθ]dr

m = 2π∫r³dr    ∫sinθdθ = 1

m = 2π × 4     ∫r³dr = 4

m = 8π units

m = 25.133 units

5 0
3 years ago
Please help
Damm [24]

Answer:

It is a

Step-by-step explanation:

5 0
3 years ago
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